fishless cycling math question

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twincessna340a

Aquarium Advice Apprentice
Joined
Jun 16, 2010
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29
I have the 10% Ammonium Hydroxide cleaning soln. that I've been using for my fishless cycling in my 40 and 75. I was wondering what the calculations would be if I wanted a given ppm in a tank? [I want 'x' mg/L in a 'y' L tank so I should add 'z' mL of 10% NH3(aq)]

Or if someone could ballpark drops/gal that would be fine.
 
10% ammonia = 10 g/100ml or 100g/liter or 100 mg/ml

1 ppm = 1 mg/liter

40 US Gal = 150 liters

Therefore 1 ppm in 40 gal = 150 mg of ammonia needed.

<Ammonia needed in mg = Tank size in liters x ppm>

150 mg of ammonia is 1.5 ml of 10% ammonia.

<Ammonia needed in ml = Ammonia in mg / Ammonia concentration in mg/ml>



** To put everything together:
NH3 in ml = Tank size in l x ppm / NH3 concentration in mg/ml


some useful conversions from ml:
1 Teaspoon is 5 ml
Many medical droppers (NOR ALL) are 10 drops per ml
 
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