Originally Posted by bud29
Jeez, thread! WAKE UP!
Here's a riddle to get the people back on here:
Mr. Ocellaris Clowfish was lonely in his anemone. He decided to visit his clownfish friends in their anemones. He decided to visit Mr. Black first, Mr. Maroon second, and Mr. Two-Banded third. Mr. Ocellaris planned his trip. He calculated that the distance from his anemone to Mr. Black's anemone would be 1/3 of his trip. He calculated that the distance from Mr. Black's anemone to Mr. Maroon's anemone would be 1/5 of his trip. And he knew that the distance from Mr. Maroon's aneomone to Mr. Two-Banded's anemone was 2,761 inches.
To the nearest inch, how long is it from Mr. Ocellaris's Anemone to Mr. Two-Banded's anemone?
1/3 + 1/5 = 5/15 + 3/15 = 8/15
Making the trip to two banded 7/15 so...
7/15= 2761, making 1/15= 394.43, thus 15/15 (1 trip) would be 5916.43. Rounded to the nearest inch is 5916 inches.
My brain hurts. Am I right?