Also, there is no "twist" to things. In other words, the tank isn't more unlevel on the left front than on the right front. So there will be no torque on the stand/tank.
If I'm doing my math correctly, the 0.22" difference in height equates to approx one quart of water
(0.22" * 30" (width of tank) * 18" (front-to-back)) * 0.5 (since it's a "wedge", it's only half))
This is 59.4 cubic inches, or about one quart. Even without the factor of 1/2, it's a half gallon. So worst case, less than 4 pounds extra on the front of the tank.
Just makes me wonder if it's something to worry about for 0.22 inches...I suppose I could get the wooden snap-off shims and just shim my way around the front and sides...