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Old 11-28-2006, 02:22 AM   #11
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Well, depending on how thick the wall is, the tank may not be all that heavy. A 10G could be made to be a nice size, half a thick as the standard 10G, and taller and wider in size. Imagine how big a circle a 29G could be.
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Old 11-28-2006, 04:19 AM   #12
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Hi Everyone,

First of all thank you all for your responses. As TropicalFish and Esra wrote I need aquarium with a circle from viewing side which looks like a cookie as Esra said . I am not looking for spherical nor rectangular to make circular opening. If I put a square aquarium and make a circle opening to look like it is circled aquarium that with make my viewing side of aquarium between 15 and 20 inches which is almost double less than the current circle. Let me describe better. The circle hole is already made in the wall. The wall supports stairs that go to my second floor thus if I have spherical aquarium it will stick out on both sides and influence the walking on the stairs. I was thinking to make additional small opening on the back of the wall above the circle for the necessary filters and lighting. The wall is thick between 7-8 inches and the circle is in diameter of 30 inches. Hope the explanation helps if not I can post a picture let me know.


Alex
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Old 11-28-2006, 10:54 AM   #13
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you will definately have to get a custom made acrylic tank. It won't be cheap.

If i do the math correctly...

Radious = R = 15 inches (since diameter is 30 inches)

Area = 3.1415 * 15 * 15 = 706in^2

Volume = 706 * 7.5 = 5301 cubic inches of water

B/c i dont know how many cubic inches of water in a gallon/liter, i'm going to have to convert to metric:

5301*2.2 = 11,662 ml of water = 11.6 liters of water /3.8 (to convert back to gallons) 3 gallons

3 gallons of water is NOT a large tank (unless i've royally screwed up somewhere.

You may be able to fit some guppies or rasbora's. But though it may LOOK big, its deciving.

Then again, i may have screwed up. Someone check my math?
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Old 11-28-2006, 02:22 PM   #14
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Quote:
Originally Posted by sudz
Then again, i may have screwed up. Someone check my math?
sorry, you did goof up the math :P the equation you used for the volume of a sphere is incorrect.

here ya go:
volume of a sphere = 4/3*pi*r^3

for a 30 inch sphere:
volume = 4/3 * pi * 15^3
volume = 14137.17 in^3

1 gallon = 231 in^3

so, 14137.17 / 231 = 61 gallons.

however, you will lose some volume at the top because you will have an opening at the top, plus the water level will be below the top opening, and the internal diameter of the sphere will be less than the 30 inches stated.

so, that ideal 61 gallons will probably be down to 50 or less by the time all the other factors are included.

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Old 11-28-2006, 03:40 PM   #15
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Its not a sphere though. Its a cylindar?
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Old 11-28-2006, 04:11 PM   #16
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In any case 231 in^3 to a gallon (with your cylinder numbers) will be just under 23 gallons.

There would also have to be some sort of opening(s) on the top to get the equipment in.

This is going to have to be a custom job for sure.
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Old 11-28-2006, 04:31 PM   #17
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Boy was I off! lol, Yes, definately Custom :P It'd be nice if you could just... put a rectangular one in there... and fill in the bottom portion of the hole (that the tank would make) with a cabinet and a small canister filter.

Kinda like... this (attached picture)
Whenever curves are involved, price goes up ALOT.

hehe... puting a rectangle in a round hole

As well, i'm sure that there is little support around the perimiter of the circle... you could probablyknock out the drywall whhere the corners of the tank are and put a bigger rectangle in. It could be flush with the studs in the wall, most likely at each outer limit of the circle)

Can any canister filters be operated sideways? it may fit underneath. If not, then i'm guessing an under-gravel filter? *srhugs*

whatever happens, let us know!
Attached Images
File Type: jpg idea_146.jpg (153.9 KB, 25 views)
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Old 11-28-2006, 04:55 PM   #18
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My calculations say that there would be about 21G in there, not bad:

Area of the circle: Pi * (30in/2)^2 = 706.85in^2
Depth of cylinder: let's say 7 inches.
Area times height: 706.85in^2 * 7in = 4947.95 cubic inches.

4947.95 cubic inch = 21.42 gallons [US, liquid]
According to OnlineConversion.com.
Am I wrong?

edit: I just realized I forgot to square the radius.
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Old 11-28-2006, 06:11 PM   #19
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Hello Everyone,

I see everyone is doing the math . I am not sure how many gallons will fit in but it is not a spherical equation but a cylindrical with diameter of 30 inches and depth/high of 7.5 inches. I should say again cylindrical but with the circle on the view side not on the top. I am attaching a picture of the circle. Meanwhile I got an idea is it possible that I can actually built in the aquarium like an indoor fountain for example to seal the glass circles and make the sides with water isolation material, just an idea maybe a crazy one . As for the opening yes there will be opening on the top of the circle but from the back side so on on the front side of the aquarium the opening want be seen. So the opening will be above the circle. Currently there is only one glass just to cover the back side of the circle.
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File Type: jpg wall_175.jpg (123.4 KB, 30 views)
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Old 11-28-2006, 06:19 PM   #20
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Hmmm
You could just a a rectangular tank, and have the corners not visible. It is easier to work with, and no custom stuff is needed, except maybe an extra tall stand from the back.
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