I have been doing a lot of lighting research on my own and czcz mentioned I should post my findings here. First of all, I completely agree with everything Wizard~Of~Oz and czcz have previously stated.
Their research on lumens/watt seems to have all been done on 4' tubes. However, the same bulb at different lengths produce different lumens/watt. This is true for all bulb types. Take for example the 48" T12 GE Chroma 50 (Sunshine) bulb. It produces 2250 lumens with 40 watts giving it 56.25 lumens/watt. Now take a look at the 24" T12 GE Chroma 50 bulb. It produces 875 lumens at 20 watts giving it 43.75 lumens/watt. The pattern is that the smaller the bulb size, the lower the lumens/watt number eventually becomes.
This means that unless you have 4' tubes, you simply can not add up your wattage and multiply it by your bulb types conversion factors they have found. Instead, you must use the rated lumens in your calculations.
Formula: Total Lumens / Surface Area / 5.63
(5.63 is Wizard~Of~Oz lumens/inch^2 to achieve 1 WPG)
Example:
Total lumens: 620 (1 GE Chroma 50 18" T8)
Surface Area: 200 (Stadard 10 gallon)
620 / 200 = 3.1 lumens/inches^2
3.1 / 5.63 = 0.55 WPG
I bet all you 10 gallon people thought you were getting more light off that single strip. And I'm only going to make it worse for you.
Has anyone ever considered ballast factor? In Wizard~Of~Oz's findings he assumes 1.0 ballast factor. However, most magnetic ballast have a ballast factor of 0.94 while most electronic ballast have a ballast factor of 0.88. Wizard~Of~Oz assumed the WPG rule was developed over a 55 gallon take using 4' T12 bulbs. I'm going to add to this by assuming they were using average magnetic ballast. In his example he uses a 4' T12 bulb rated at 2350 lumens. With a magnetic ballast, this results in 2350 * 0.94 = 2209 lumens or 2209 / 40 = 55.23 lumens/watt. This means that 1 WPG (55 watts) of this lighting gives us 55 * 55.23 = 3037.38 lumens or 3037.38 / 576 = 5.27 lumens/inch^2 (576 is 55 gallon surface area in inches^2).
So our final formula will be Total Lumens * Ballast Factor / Surface Area / 5.27
Example using previous 10 gallon tank:
620 * 0.88 (Electronic ballast) = 545.6 lumens
545.6 / 200 = 2.73 lumens/inches^2
2.73 / 5.27 = 0.52 WPG
Is 0.55 WPG and 0.52 WPG really that big of a difference? No. But it does play a bigger part on larger tanks with more lighting. That and some ballast have really extreme ballast factors. I have seen some as low as 0.6 and as high as 1.2. In those cases you may want to consider this approach. In most other cases the first aproach should be fine and is simpler.
For a smaller tank you know you already have less light than what the WPG rule gives. I just want to make the point that you have even less light that what you previously thought.
I hope this wasn't too confusing and that it helps.
Edit: More on ballast factors. Most electronic ballast have a ballast factor that changes depending on how many of the leads you use. For example an electronic ballast with 4 leads is rated at 0.88. However, when only 3 leads are used, the ballast factor is actually 1.0. With only 2 leads used it becomes 1.12 and with only 1 lead use it is 1.24. This is normal and is similar to overdriving lights. Just something to think about.
Their research on lumens/watt seems to have all been done on 4' tubes. However, the same bulb at different lengths produce different lumens/watt. This is true for all bulb types. Take for example the 48" T12 GE Chroma 50 (Sunshine) bulb. It produces 2250 lumens with 40 watts giving it 56.25 lumens/watt. Now take a look at the 24" T12 GE Chroma 50 bulb. It produces 875 lumens at 20 watts giving it 43.75 lumens/watt. The pattern is that the smaller the bulb size, the lower the lumens/watt number eventually becomes.
This means that unless you have 4' tubes, you simply can not add up your wattage and multiply it by your bulb types conversion factors they have found. Instead, you must use the rated lumens in your calculations.
Formula: Total Lumens / Surface Area / 5.63
(5.63 is Wizard~Of~Oz lumens/inch^2 to achieve 1 WPG)
Example:
Total lumens: 620 (1 GE Chroma 50 18" T8)
Surface Area: 200 (Stadard 10 gallon)
620 / 200 = 3.1 lumens/inches^2
3.1 / 5.63 = 0.55 WPG
I bet all you 10 gallon people thought you were getting more light off that single strip. And I'm only going to make it worse for you.
Has anyone ever considered ballast factor? In Wizard~Of~Oz's findings he assumes 1.0 ballast factor. However, most magnetic ballast have a ballast factor of 0.94 while most electronic ballast have a ballast factor of 0.88. Wizard~Of~Oz assumed the WPG rule was developed over a 55 gallon take using 4' T12 bulbs. I'm going to add to this by assuming they were using average magnetic ballast. In his example he uses a 4' T12 bulb rated at 2350 lumens. With a magnetic ballast, this results in 2350 * 0.94 = 2209 lumens or 2209 / 40 = 55.23 lumens/watt. This means that 1 WPG (55 watts) of this lighting gives us 55 * 55.23 = 3037.38 lumens or 3037.38 / 576 = 5.27 lumens/inch^2 (576 is 55 gallon surface area in inches^2).
So our final formula will be Total Lumens * Ballast Factor / Surface Area / 5.27
Example using previous 10 gallon tank:
620 * 0.88 (Electronic ballast) = 545.6 lumens
545.6 / 200 = 2.73 lumens/inches^2
2.73 / 5.27 = 0.52 WPG
Is 0.55 WPG and 0.52 WPG really that big of a difference? No. But it does play a bigger part on larger tanks with more lighting. That and some ballast have really extreme ballast factors. I have seen some as low as 0.6 and as high as 1.2. In those cases you may want to consider this approach. In most other cases the first aproach should be fine and is simpler.
For a smaller tank you know you already have less light than what the WPG rule gives. I just want to make the point that you have even less light that what you previously thought.
I hope this wasn't too confusing and that it helps.
Edit: More on ballast factors. Most electronic ballast have a ballast factor that changes depending on how many of the leads you use. For example an electronic ballast with 4 leads is rated at 0.88. However, when only 3 leads are used, the ballast factor is actually 1.0. With only 2 leads used it becomes 1.12 and with only 1 lead use it is 1.24. This is normal and is similar to overdriving lights. Just something to think about.